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A mixture of 2 moles of helium gas ((ato...

A mixture of 2 moles of helium gas (`(atomic mass)=4a.m.u`) and 1 mole of argon gas (`(atomic mass)=40a.m.u`) is kept at 300K in a container. The ratio of the rms speeds `((v_(rms)(helium))/((v_(rms)(argon))` is

A

0.32

B

3.16

C

2.24

D

0.45

Text Solution

Verified by Experts

The correct Answer is:
B
`((V_(rms))_(He))/((V_(rms))_(Ar))=sqrt((M_(Ar))/(M_(He)))=sqrt((40)/(4))=sqrt(10)=3.16`
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