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Cpand Cv are specific heats at constant ...

`C_p`and `C_v` are specific heats at constant pressure and constant volume respectively. It is observed that `C_p - C_v = a` for hydrogen gas
`C_p = C_V = b` for nitrogen gas
The correct relation between a and b is:

A

a=28b

B

a=`(1)/(14)`b

C

a=b

D

a=14b

Text Solution

Verified by Experts

The correct Answer is:
D
`C=(M_O)S`
For `H_2` as well as `N_2`-
`(M_O)S_p-(M_O)S_v=R`
`S_p-S_v=(R)/(M_O)`
For `H_2` gas -
`S_p-S_v=(R)/(2)=a`
For `N_2` gas-
`S_p-S_v=(R)/(28)=b`
So, `a/b=(R/2)/((R)/(28))=14 implies a = 14 b`
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