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The energy emitted per second by a black...

The energy emitted per second by a black body at `27^(@)C` is 10 J. If the temperature of the black body is increased to `327^(@)C` , the energy emitted per second will be

A

20 J

B

40 J

C

80 J

D

160 J

Text Solution

Verified by Experts

The correct Answer is:
D
(Q) = Energy emitted by black body A`sigma T^4 t`
`implies Q prop T^4`
`implies Q_2 =Q_1 ((T_2)/(T_1))^4=10((273+327)/(273+27))^4`
`implies Q_2=10 ((600)/(300))^4 =160 J`.
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