Home
Class 11
PHYSICS
A body cools from 50^(@)C to 40^(@)C in ...

A body cools from `50^(@)C` to `40^(@)C` in `5` minutes. The surrounding temperature is `20^(@)C`. What will be its temperature `5` minutes after reading `40^(@)C`? Use approximate method.

Text Solution

Verified by Experts

The correct Answer is:
3.33
`((theta_(1)-theta_(2))/t)=alpha((theta_(1)+theta_(2))/2-theta_(0))`
`rArr (50 - 40 )/(5xx60) = alpha ((50+40)/2-20)`
` :. alpha = 10/(300xx25) = 1/750`
Now again ,
`(40-T)/300 = 1/750 [(T+40-40)/2]`
`rArr 400 - 10 T = 2T `
`rArr 12 T = 400 `
` :. T = 400/12 rArr T = 100/3 .^(@)C`
Promotional Banner

Similar Questions

Explore conceptually related problems

A body cools from 50^(@)C to 40^(@)C in 5 min. The surroundings temperature is 20^(@)C . In what further times (in minutes) will it cool to 30^(@)C ?

A body cools from 50^@C to 40^@C in 5 mintues in surrounding temperature 20^@C . Find temperature of body in next 5 mintues.

A metallic sphere cools from 50^(@)C to 40^(@)C in 300 seconds. If the room temperature is 20^(@)C then its temperature in next 5 minutes will be -

A body cools from 60^(@)C to 50^(@)C in 10 minutes when kept in air at 30^(@)C . In the next 10 minut es its temperature will be

A body cools from 50C to 40C in 5min .The surroundings temperature is 20C .In what further time (in minutes) will it cool to 30C

A body cools from 70^(@)C to 50^(@)C in 5minutes Temperature of surroundings is 20^(@)C Its temperature after next 10 minutes is .

The temperature of a body falls from 52^(@)C to 36^(@)C in 10 minutes when placed in a surrounding of constant temperature 20^(@)C . What will be the temperature of the body after another 10min . (Use Newton's law of cooling)

A body cools from 50^(@)C to 46^(@)C in 5 minutes and to 40^(@)C in the next 10 minutes. The surrounding temperature is :

A body cools from 50^(@)C to 40^(@)C is 5 minutes when its surrounding are at a constant temperature of 20^(@)C . How long will it take for it to cool by another 10^(@)C ?

A body cools from 70^(@)C to 50^(@)C in 6 minutes when the temperature of the surrounding is 30^(@)C . What will be the temperature of the body after further 12 minutes if coolilng proseeds ac cording to Newton's law of cooling ?