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A long straight wire carrying current ...

A long straight wire carrying current of `30 A` is placed in an external unifrom magnetic field of induction `4xx10^(4) T`. The magnetic field is acting parallel to the direction of current. The maggnetic of the resultant magnetic inuduction in tesla at a point `2.0 cm` away form the wire is

A

`10^(-4)`

B

`3 xx 10^(-4)`

C

`5 xx 10^(-4)`

D

`6 xx 10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
C

`B_(1) = 4 xx 10^(-4) T , I = 30 A `
`B_(2) = (mu_(0) I)/(2pi r) = (4pi xx 10^(-7) xx 30)/(2pi xx 10^(-2) xx 2)`
`= 3 xx 10^(-4) T`
`therefore B_("net") = sqrt(B_(1)^(2) + B_(2)^(2)) = 5 xx 10^(-4) T `
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