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A particle carrying a charge equal to 10...

A particle carrying a charge equal to `100` times the charge on an electron is rotating per second in a circular path of radius `0.8 metre`. The value of the magnetic field produced at the centre will be (`mu_(0)=` permeability for vacuum)

A

`(10^(-7))/(mu_(0))`

B

`10^(-17) mu_(0)`

C

`10^(-6) mu_(0)`

D

`10^(-7) mu_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B

Current (I) = 100 e = `100 xx 1.6 xx 10^(-19) = 1.6 xx 10^(-17) A`
`B_("Centre") = (mu_(0) I)/(2R) = (4pi xx 10^(-7) xx 1.6 xx 10^(-17))/(2 xx 0.8) = 10^(-17) mu_(0)`
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