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The current in the windings on a toroid ...

The current in the windings on a toroid is 2.0A. There are 400 turns and the mean circumferential length is 40cm. If the inside magnetic field is 1.0T, the relative permeability is near to

A

100

B

200

C

300

D

400

Text Solution

Verified by Experts

The correct Answer is:
D
`B = (mu_(0) mu_(r) IN)/(2pi r)`
`N = 400 , 2pi r = 40 implies r = ((40)/(2pi)) xx 10^(-2)` m
`B = 1 T`
`I = (4pi xx 10^(-7) xx mu_(r) xx 2 xx 400 xx 2pi)/(2 xx 40 xx 10^(-2) xx pi )`
`implies mu_(r) = 398.089 ~~400` (approx)
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