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A part of a long wire carrying a current...

A part of a long wire carrying a current `i` is bent into a circle of radius `r` as shown in figure. The net magnetic field at the centre `O` of the circular loop is

A

`(mu_(0) i)/(4r)`

B

`(mu_(0) i)/(2r)`

C

`(mu_(0) i)/(2pi r) (pi + 1)`

D

`(mu_(0) i)/(2pi r) ( pi - 1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`B = B_("loop") + B_("wire")`
`= (mu_(0) i)/(2r) + (mu_(0) i)/(2pi r) = (mu_(0) i)/(2r) [ 1 + (1)/(pi) ] = (mu_(0) i)/(2pi r) [pi + 1] odot`
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