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An electron eneters the space between th...

An electron eneters the space between the plates of charged capacitor as shown. The carge density on the plate is `sigma`, electric intensity in the space between the plates is E, A unifrom magnetic field B aslo exists B also exists in the spae perpendicular to the direction of E.
The electron moves perpendicular to both E and B without any change in direction. The time taken by the electron to travel a distance l in the space is

A

`(sigma l)/(epsi_(0) B)`

B

`(sigma B)/(epsi_(0) l)`

C

`(epsi_(0) lB)/(sigma)`

D

`(epsi_(0) l)/(sigma B)`

Text Solution

Verified by Experts

The correct Answer is:
C
`v = (E)/(B) = (sigma)/(epsi_(0) B)`
`t = (1)/(v) = (epsi_(0) Bl)/(sigma)`
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