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The operating magnetic field for acceler...

The operating magnetic field for accelerating protons in a cyclotron oscillator having frequency of 12 MHz is `(q= 1.6 xx 10^(-19) C, m_(p) = 1.67 xx 10^(-27) kg and 1 MeV = 1.6 xx 10^(-13J))`

A

0.8 T

B

1.6 T

C

2.0 T

D

3.2 T

Text Solution

Verified by Experts

The correct Answer is:
A
`f = (Bq)/(2nm) implies B = (2nmf)/(q)`
`implies B = (2 xx 3.14 xx 1.67 xx 10^(-27) xx 12 xx 10^(6))/(1.6 xx 10^(-19))`
`implies B = 0.78 = 0.8 T`
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