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A particle with charge q, moving with a ...

A particle with charge `q`, moving with a momentum `p`, enters a uniform magnetic field normally. The magnetic field has magnitude `B` and is confined to a region of width `d`, where `dlt(p)/(Bq)`. If the particle is deflected by an angle `theta` in crossing the field then

A

`sin theta = (Bqd)/(P)`

B

`sin theta = (P)/(Bqd)`

C

`sin theta = (BP)/(qd)`

D

`sin theta = (Pd)/(Bq)`

Text Solution

Verified by Experts

The correct Answer is:
A
As `sin theta = (d)/( r)` And Radius = `(mv)/(Bq)`
`r = (P)/(Bq)`
`therefore sin theta = (Bqd)/(P)`
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