Home
Class 12
PHYSICS
An electron and a proton, both having th...

An electron and a proton, both having the same kinetic energy, enter a region of uniform magnetic field, in a plane perpendicular to the field. If their masses are denoted by `m_(e)` and `m_(p)` respectively, then the ratio of the radii (electron to proton) of their circular orbits is

A

`sqrt((m_(p))/(m_(e)))`

B

`sqrt((m_(e))/(m_(p)))`

C

`(m_(e))/(m_(p))`

D

1

Text Solution

Verified by Experts

The correct Answer is:
B

Since , `r = (sqrt(2mk))/(qB) implies r prop sqrtm`
`implies (r_(e))/(r_(p)) = sqrt((m_(e))/(m_(p)))`
Promotional Banner

Similar Questions

Explore conceptually related problems

An electron and a proton have equal kinetic energies. They enter in a magnetic field perpendicularly, then

A proton and an electron are projected into a region of uniform magnetic field in a direction perpendicular to the field. If they have the same initial velocities then

An electron and a proton with equal momentum enter perpendicularly into a uniform magnetic field, then

An electron having mass 'm' and kinetic energy E enter in uniform magnetic field B perpendicularly, then its frequency will be : -

A proton and a deuteron both having the same kinetic energy, enter perpendicularly into a uniform magnetic field B . For motion of proton and deuteron on circular path or radius R_(p) and R_(d) respectively, the correct statement is

A proton and a deuteron both having the same kinetic energy enter perpendicularly in to uniform magnetic field B for motion of proton and deuteron on ciruclar path of radius R_(p) and R_(d) respectively the correct statement is

An electron and a proton are moving with the same kinetic energy along the same direction . When they pass through a uniform magnetic field perpendicular to the direction of their motion , they describe circular paths of the same radius.