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A particle of mass 0.6g and having charg...

A particle of mass `0.6g` and having charge of `25 nC` is moving horizontally with a uniform velocity `1.2xx10^(4)ms^(-1)` in a uniform magnetic field, then the value of the magnetic induction is `(g=10ms^(-2))`

A

Zero

B

10 T

C

20 T

D

200 T

Text Solution

Verified by Experts

The correct Answer is:
C
m = 0.6 g , q = `25 xx 10^(-9)C , v = 1.2 xx 10^(4)` m/s
Since , v = constant
`|F_(m)| = mg implies mg = qvB`
`B = (mg)/(qv) = (0.6 xx 10^(-3) xx 10)/(25 xx 10^(-9) xx 1.2 xx 10^(4)) implies B = 20T`
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