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A circular coil of radius 4 cm and of 20...

A circular coil of radius `4 cm` and of `20` turns carries a current of `3` amperes. It is placed in a magnetic field of intensity of `0.5 weber//m^(2)`. The magnetic dipole moment of the coil is

A

0.15 ampere - `m^(2)`

B

0.3 ampere - `m^(2)`

C

0.45 ampere - `m^(2)`

D

0.6 ampere - `m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
M = NIA
`= 20 xx 3 xx pi (4 xx 10^(-2))^(2) = 0.3` ampere`-m^(2)`
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