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A wire of length 2 m is bent into a circ...

A wire of length 2 m is bent into a circular loop. When a current of 1 A is passed through the loop, then the magnetic moment of the loop is

A

`2pi A m^(2)`

B

`pi //2 Am^(2)`

C

`pi //4 A m^(2)`

D

`1//pi Am^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`m = IA = I ((L)/(2pi))^(2) pi`
`m = (1 xx 2 xx 2)/(4pi ) = (1)/(pi) A//m^(2) , (because L = 2pi r)`
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