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The magnetic field due to a current carr...

The magnetic field due to a current carrying circular loop of radius 3 cm at a point on the axis at a distance of 4cm from the centre is `54muT`. What will be its vlue at the centre of loop?

A

`250 muT`

B

`150 muT`

C

`125 muT`

D

`75 muT`

Text Solution

Verified by Experts

The correct Answer is:
A

`(B_("center"))/(B_("axis"))=(1+x^2/r^2)^(3//2)implies (B_("center"))/54=[1+(4/3)^2]^(-3//2)`
`implies B_("center")= 250 xx10^(-6) T`
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