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A non - popular loop of conducting wire ...

A non - popular loop of conducting wire carrying a current `I` is placed as shown in the figure . Each of the straighrt sections of the loop is of the length ` 2a`. The magnetic field due to this loop at the point `P(a, 0 ,a)` points in the direction

A

`1/sqrt2(-hatj+hatk)`

B

`1/sqrt3(-hatj+hatk+hati)`

C

`1/sqrt3(hatj+hatj+hatk)`

D

`1/sqrt2 (hati + hatk)`

Text Solution

Verified by Experts

The correct Answer is:
D
The magnetic field at P (a, 0, a) due to the loop is equal to the vector sum of the magnetic fields produced by loops ABCDA and AFEBA as shown in the figure.
Magnetic field due to loop ABCDA will be along `hati` and due to loop AFEBA, along `hatk` Magnitude of magnetic field due to both the loops will be equal.
Therefore, direction of resultant magnetic field at P will be `1/sqrt2 (hati + hatk)`
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