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Two particles A and B of masses mA and m...

Two particles `A` and `B` of masses `m_A` and `m_B` respectively and having the same charge are moving ina plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are `v_A` and `v_B` respectively and the trajectories are as shown in the figure. Then,

A

`m_A v_A lt m_B v_B`

B

`m_A v_A gt m_B v_B`

C

`m_A m_B lt v_A lt v_B`

D

`m_A =m_B and v_A=v_B`

Text Solution

Verified by Experts

The correct Answer is:
B
`r=(mv)/(qB)implies r prop mv implies r_A gt r_B`
`m_Av_Agt m_Bv_B`
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