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A coil of area 100 cm^(2) has 500 turns....

A coil of area `100 cm^(2)` has `500` turns. Magnetic field of `0.1 "weber"//"meter"^(2)` is perpendicular to the coil. The field is reduced to zero in `0.1` second. The induced `e.m.f.` in the coil is

A

1 V

B

5 V

C

50 V

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
B
`e=(-NDeltavarphi)/(Deltat)=(-N(0-BA))/(Deltat)=(500xx100xx10^(-4)xx0.1)/0.1`
e = 5V.
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