Home
Class 12
PHYSICS
A conducting circular loop is placed in ...

A conducting circular loop is placed in a uniform magnetic field `0.04T` with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at `2mm//sec` . The induced emf in the loop when the radius is `2cm` is

A

3.2 `pimuV`

B

4.8 `pimuV`

C

0.8 `pimuV`

D

1.6 `pimuV`

Text Solution

Verified by Experts

The correct Answer is:
A
`|e|=(dvarphi)/dt=B(dA)/dt=Bd/dt(pir^(2))`
`rArr|e|=2piBr(dr)/dt`
`rArr|e|=2pixx0.04xx2xx10^(-2)xx2xx10^(-3)`
= `3.2pixx10^(-6)V=3.2pimuV`.
Promotional Banner

Similar Questions

Explore conceptually related problems

A conduction circular loop is placed in a uniform magnetic field 0.02T with its place normal to the field . The radius of loop starts shrinking at a rate of 1.0 mm//sec . Then induced emf in the loop at an instant when the radius is 2 cm :-

A conducting circular loop is placed in a uniform magnetic field, B=0.025T with its plane perpendicular to the loop. The radius of the loop is made to shrink at a constant rate of 1 mms^(-1) . The induced emf when the radius is 2 cm is

A conducting circular loop is placed is a uniform magnetic field B =0.20 T with its plane perpendicualr to the field . Somehow, the radius of the loop starts shrinking at a constant rate of 1.0 mm s^(-1). Find the induced emf in the loop at an instant when the radius is 2 cm.

A conducing circular loop is placed in a uniform magnetic field of 0.02 T, woth its plane perpendicular to the field. If the redius of the loop starts shrinking at a constant rate of 1.0 mm//s , then find the emf induced in the loop, at the instant when radius is 4 cm.

A conducting square loop is placed in a magnetic field B with its plane perpendicular to the field. Now the sides of the loop start shrinking at a constant rate alpha. the induced emf in the loop at an instant when its side is a is