Home
Class 12
PHYSICS
A square of side L metres lies in the xy...

A square of side L metres lies in the xy-plane in a region, where the magnetic field is given by `B=B_(0)(2hati+3hatj+4k)T`, where `B_(0)` is constant. The magnitude of flux passing through the square is

A

`2B_(0)L^(2)Wb`

B

`3B_(0)L^(2)Wb`

C

`4B_(0)L^(2)Wb`

D

`sqrt29B_(0)L^(2)Wb`

Text Solution

Verified by Experts

The correct Answer is:
C
Here, `A=L^(2)hatkandB=B_(0)(2hati+3hatj+4hatk)T`
`varphi=B*A=B_(0)(2hati+3hatj+4hatk)*L^(2)hatk=4B_(0)L^(2)Wb`.
Promotional Banner

Similar Questions

Explore conceptually related problems

A square of side L meters lies in the x-y plane in a region, where the magnetic field is give by B = B_(0) (2 hati + 3 hat j + 4 hatk) T, where B_(0) is constant. The magnitude of flux passing through the square is

A square of side x m lies in the x-y plane in a region, when the magntic field is given by vecB=B_(0)(3hati+4hatj+5hatk) T, where B_(0) is constant. The magnitude of flux passing through the square is

A square of side 'a' is lying in xy plane such that two of its sides are lying on the axis. If an electric field vec(E)=E_(0)xhat(k) is applied on the square. The flux passing through the square is :

Figure shows a square loop carrying current I is present in the magnetic field which is given by vecB=(B_(0)z)/(L)hatj+(B_(0)y)/(L)hatk where B_(0) is positive constant. Which of the following statement(s) is/are correct?

The electric field in a region is given by E=ahati+bhatj . Hence as and b are constants. Find the net flux passing through a square area of side I parallel to y-z plane.

A circular loop of radius R carrying current I is kept in XZ plane. A uniform and constant magnetic field vecB=(B_(0)hati+2B_(0)hatj+3B_(0)hatk) exists in the region ( B_(0)- a positive constant). Then the magnitude of the torque acting on the loop will be

A wire of length l metre carries a current I ampere along the Y-axis. A magnetic field, vecB=B_0(hati+hatj+hatk) tesla exists in space. Find the magnitude of the force on the wire.