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If a coil of 40 turns and area 4.0 cm^(...

If a coil of `40` turns and area `4.0 cm^(2)` is suddenly remove from a magnetic field, it is observed that a charge of `2.0xx10^(-4)C` flows into the coil. If the resistance of the coil is `80Omega`, the magnetic flux density in `Wb//m^(2)` is

A

0.5

B

`1.0`

C

1.5

D

`2.0`

Text Solution

Verified by Experts

The correct Answer is:
B
`q=(NDeltavarphi)/R`
`rArrNDeltavarphi=2xx10^(-4)xx80rArrNBA=2xx10^(-4)xx80`
`rArrB=(2xx10^(-4)xx80)/(40xx4xx10^(-4))=1Wb//m^(2)`.
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