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The magnetic field B=2t+4t^(2) (where t ...

The magnetic field `B=2t+4t^(2)` (where t = time) is applied perpendicular to the plane of a circular wire of radius r and resistance R. If all the units are in SI the electric charge that flows through the circular wire during t = 0 s to t = 2 s is

A

`(6pir^(2))/R`

B

`(20pir^(2))/R`

C

`(32pir^(2))/R`

D

`(48pir^(2))/R`

Text Solution

Verified by Experts

The correct Answer is:
B
`B=2t+4t^(2)`
`q=(Deltavarphi)/R=(pir^(2)(B_(2)-B_(1)))/R=(pir^(2)(2xx2+4xx4))/R=(20pir^(2))/R`.
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