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the inductance of a closed-packed coil o...

the inductance of a closed-packed coil of `400` turns is `8mH`. `A` current of `5mA` is passed through it. The magnetic flux through each turn of the coil is

A

`1/(4pi)mu_(0)Wb`

B

`1/(2pi)mu_(0)Wb`

C

`1/(3pi)mu_(0)Wb`

D

`0.4mu_(0)Wb`

Text Solution

Verified by Experts

The correct Answer is:
A
`Nvarphi=LIrArrvarphi=(LI)/N=(8xx10^(-3)xx5xx10^(-3))/400`
`rArrvarphi=10^(-7)=mu_(0)/(4pi)Wb`.
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