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The number of turns of primary and secon...

The number of turns of primary and secondary coils of a transformer are 5 and 10 respectively and the mutual inductance of the tranformar is 25 henry. Now the number of turns in the primary and secondary of the transformar are made 10 and 5 respectivaly. The mutual inductance of the transformar in henry will be

A

6.25

B

12.5

C

25

D

50

Text Solution

Verified by Experts

The correct Answer is:
C
`MpropN_(1)N_(2)`
`M_(1)/M_(2)=(N_(1)N_(2))/(N_(1)N_(2))rArrM_(2)=M_(1)xx(N_(1)N_(2))/(N_(1)N_(2))`
= `25xx(10xx5)/(5xx10)=25H`.
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