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A coil of self-inductance 50 henry is j...

A coil of self-inductance `50` henry is joined to the terminals of a battery of e.m.f. `2` volts through a resistance of `10ohm` and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to `1//e` of its steady value is

A

500 seconds

B

50 seconds

C

5 seconds

D

0.5 seconds

Text Solution

Verified by Experts

The correct Answer is:
C
`t=tau=L/R=50/10=5sec`
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