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An ideal coil of 10 henry is joined in s...

An ideal coil of `10` henry is joined in series with a resistance of `5` ohm and a battery of `5` volt. `2` second after joining, the current flowing in ampere in the circuit will be

A

`e^(-1)`

B

`(1-e^(-1))`

C

(1-e)

D

e

Text Solution

Verified by Experts

The correct Answer is:
B
`i=i_(0)(1-e^((-t)/tau)),tau=L/R=10/5=2`
`rArri_(0)=5/5=1amp`
`rArr1(1-e^(-1))=(1-e^(-1))`.
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