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The number of turns of the primary and t...

The number of turns of the primary and the secondary coils of a transformer are 10 and 100 respectively. The primary voltage and the current are given as 2 V and 1 A. Assuming the efficiency of the transformer as 90%, the secondary voltage and the current respectively are

A

20 V and 0.1 A

B

0.2 V and 1 A

C

20 V and 0.09 A

D

0.2 V and 0.9 A

Text Solution

Verified by Experts

The correct Answer is:
C
`N_(P)=10,N_(S)=100,V_(P)=2V,I_(P)=1A`
`eta=0.9=(V_(S)I_(S))/(V_(P)I_(P))`
`rArr(0.9I_(P))/I_(S)=V_(S)/V_(P)=N_(S)/N_(P)=100/10rArrI_(S)=0.09I_(P)=0.09A`
Now, `V_(S)/V_(P)=N_(S)/N_(P)rArrV_(S)/2=100/10rArrV_(S)=20"Volt"`
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