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An inductor coil stores 32 J of magnetic...

An inductor coil stores 32 J of magnetic field energy and dissipates energy as heat at the rate of 320 W when a current of 4 A is passed through it. Find the time constant of the circuit when this coil is joined across on ideal battery.

Text Solution

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The correct Answer is:
`0.2`
From `U_B=1/2LI^2 ,32=1/2L(4)^2`
or L =4 H
Also `P=I^2 R` or `R=P/(I^2) = 320/((4)^2) Omega = 20 Omega`
Thus, `tau =L/R = (4H)/(20 Omega) = 0.2s`
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