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A thin semicircular conducting ring of r...

A thin semicircular conducting ring of radius `R` is falling with its plane vertical in a horizontal magnetic induction `B`. At the position `MNQ`, the speed of the ring is `V` and the potential difference developed across the ring is

A

Zero

B

`BvpiR^2//2` and M is at higher potentinal

C

`piRBV` and Q is at higher potential

D

2RBV and Q is at higher potential

Text Solution

Verified by Experts

The correct Answer is:
D
Rate of decrease of area of semicircular ring `=(-dA)/(dt) = 2RV`
`:. e =-(dphi)/(dt)=-B (dA)/(dt)=B(2RV)`
= 2 BRV (Q as higher potential)
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