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A coil of inductance 300mh and resistanc...

A coil of inductance `300mh` and resistance `2Omega` is connected to a source of voltage `2V`. The current reaches half of its steady state value is

A

0.15 s

B

0.3 s

C

0.05 s

D

0.1 s

Text Solution

Verified by Experts

The correct Answer is:
D
`i=i_0(1-e^(-t//tau))`
`tau =L/R=(300 xx10^(-3))/2 = 0.15`
`implies i_0/2 =i_0(1-e^(-t//0.15))`
`implies e^(-(t)/(0.15))=1/2implies-t/(0.15)`ln (e) =`ln(1/2)`
`implies t=0.69xx0.15 implies t = 0.1 sec`
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