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An inductor (L = 100 mH), a resistor (R ...

An inductor (L = 100 mH), a resistor `(R = 100Omega)` and a battery (E = 100 V) are initially connected in series as shown in the figure. After a long time the battery is disconnected after short circuiting the points A and B. The current in the circuit 1 ms after the short circuit is

A

e A

B

0.1 A

C

1A

D

1/e A

Text Solution

Verified by Experts

The correct Answer is:
D
During discharge of inductors
`i=i_0e^(-t//tau),tau=L/R`
`implies i=E/Re^((-Rt)/(L))impliesi=100/100e^((-100xx10^(-3))/(100xx10^(-3))=1/eA`
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