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The self induced emf of a coil is 25 vol...

The self induced emf of a coil is 25 volts. When the current in it is changed at uniformed rate from 10 A to 25 A in 1s, the change in the energy of the inductances is

A

540J

B

740 J

C

637.5J

D

437. 5 J

Text Solution

Verified by Experts

The correct Answer is:
D
`|E|=(Ldi)/(dt)`
`25 =L xx ((25-10))/(1)implies L=5/3 H`
Energy of inductor, `E=1/2 Li^2`
`implies DeltaE =1/2 xx 5/3 [625 -100]J`
`DeltaE = 437.5J`
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