Home
Class 12
PHYSICS
If a current I given by l(o) sin(omegat-...

If a current I given by `l_(o) sin(omegat-pi//2)` flows in an AC circuit across which an AC potential of `E_(0)`.` sin (omegat)` has been applied, then the power consumption P in the circuit will be

A

`P = (E_(0) I_(0))/(sqrt(2))`

B

`P = sqrt(2) E_(0) I_(0)`

C

`P = (E_(0) I_(0))/(2)`

D

`P = 0 `

Text Solution

Verified by Experts

The correct Answer is:
D
Since `, phi = (pi)/(2)`
`P = V_(rms) I_(rms) cos phi = 0 `
Promotional Banner

Similar Questions

Explore conceptually related problems

An a.c. emf of e=220 sin omega t is applied across the capacitor, the power consumption is

For an AC circuit V=15sin omegat and I=20cos omegat the average power consumed in this circuit is

Voltage applied to an AC circuit and current flowing in it is given by V=200sqrt2sin(omegat+pi/4) and i=-sqrt2cos(omegat+pi/4) Then, power consumed in the circuited will be

In an AC circuit, the current is given by i=5sin(100t-(pi)/2) and the AC potential is V=200sin(100) volt. Then the power consumption is

In an AC circuit the voltage applied is E = E_(0) sin omega t . The resulting current in the circuit is I = I_(0) sin (omega t - (pi)/(2)) . The power consumption in the circuit is given by

The alternating emf of e=e_(0) sin omegat is applied across capacitor C. the current through the circuit is given by

When a voltage v_(s)=200sqrt2 sin (omega t=15^(@)) is applied to an AC circuit the current in the circuit is found to be i=2som (omegat+pi//4) then average power consumed in the circuit is

An alternating voltage V = V_(0) sin omegat is applied across a circuit. As a result, a current I = I_(0) sin (omegat – p/2) flows in it. The power consumed per cycle is

AC source represented as V = V_(0) sin omega t is applied to a circuit and current I = I_(0) sin (omega t + pi//2) is found to flow through the circuit . What will be average power consumed in the circuit ?