Home
Class 12
PHYSICS
An AC source is rated at 220V, 50 Hz. Th...

An `AC` source is rated at `220V, 50 Hz.` The time taken for voltage to change from its peak value to zero is

A

50 sec

B

0.02 sec

C

5 sec

D

`5 xx 10 ^(-3) ` sec

Text Solution

Verified by Experts

The correct Answer is:
D

Time required ` = (T)/(4) = (1)/(4f) = (1)/(4 xx 50) = (1)/(200)`
`= 5 xx 10 ^(-3) ` sec
Promotional Banner

Similar Questions

Explore conceptually related problems

An AC source is rated as 220 V-50 Hz. What will be the peak voltage of this source ?

A 100 Omega iron is connected to an AC source of 220 V 50 Hz . Calculate the time taken by the current to change from its maximum value to rms value .

Find the time taken by 60 Hz a.c. to reach its peak value from zero.

An AC source rated 220 V, 50 Hz is connected to a resistor. The time taken by the current to change from its maximum to the rms value is :

An AC source is rated 220 V, 50 Hz . The average voltage is calculated in a time interval of 0.01 s . It

A resistance of 20ohms is connected to a source of an alternating potential V=220sin(100pit) . The time taken by the current to change from its peak value to r.m.s. value is

A resistance of 20 ohm is connected to a source of an alternating potential V = 200 cos (100 pi t) . The time taken by the current to change from its peak value to rms value alpha is

A resostance of 20 Omega is connected to a source of an alternating potential V=220 sin (100 pi t) . The time taken by the corrent to change from the peak value to rms value is

An alternating voltage v(t) = 220 sin 100 pt volt is applied to a purely resistive load of 50Omega . The time taken for the current to rise from half of the peak value to the peak value is :