Home
Class 12
PHYSICS
In the circuit below, the AC source the ...

In the circuit below, the `AC` source the voltage `V=20cos (omegat)` volts with `omega=2000rad//sec`. The amplitude of the current will be nearest to

A

2A

B

3.3A

C

`2 // sqrt(5) A `

D

`sqrt(5) A `

Text Solution

Verified by Experts

The correct Answer is:
A
`X_(L) = omega L = 2000 xx 5 xx 10 ^(-3) = 10 Omega `
`X_(C) = (1)/(omega C) = (1)/(2000 xx 50 xx 10^(-6)) = 10 Omega `
`Z = sqrt((R_(1) + R_(2))^(2) + (X_(L) - X_(C))^(2)) = sqrt((4 + 6)^(2)) = 10 Omega `
Current (i) ` = (20)/(10) = 2 A `
Promotional Banner

Similar Questions

Explore conceptually related problems

In the circuit shown in figure, the AC source gives a voltage V = 20 cos(2000 t ) . Neglecting source resistance, the voltmeter and ammeter readings will be (approximately)

In the circuit shown the source voltage is given as v = V_(0) sin omegat . Find the current through the source as a function of time.

In the circuit shown in figureure the AC source gives a voltage V=20cos(2000t) . Neglecting source resistance, the voltmeter and and ammeter readings will be .

In the given circuit, the AC source has omega = 100 rad/s. Considering the inductor and capacitor to be ideal, the correct choice(s) is (are)

In the given circuit the AC source has omega=100 rad s^(-1) . Considering the inductor and capacitor to be ideal, what will be the current I flowing through the circuit ?

In the given circuit, the AC source has omega=50 rad//s . Considering the inductor and capacitor to be ideal, the correct choice (s) is (are):

In a LR circuit of 3 mH dinductance and 4 Omega resistance, emf E=4cos 1000t volt is applied. The amplitude of current is

In the circuit of fig, the source freqency is omega=2000 rad s^(-1) . The current in the will be

A capacitor of capacitive reactance 5omega is connected with A.C. source having voltage V = 3 sin (omegat + pi//6) . Find rms and Peak voltage rms and peak current and instantaneous current