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A 100 V AC source of frequency 500 Hz is...

A 100 V AC source of frequency 500 Hz is connected to LCR circuit with L=8.1mH, `C=12.5muF` and `R=100Omega`, all connected in series. Find the potential (in volt) across the resistance.

Text Solution

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The correct Answer is:
100
As `X_L =2pivL = 25.4 Omega , X_C = 1/(2pivC) =25.4Omega`
`Z=sqrt(R^2+(X_L-X_C)^2)=10Omega`
`I_(rms)=E_(rms)/R = (100V)/(10Omega)=10A`
`V_R = I_("rnms")R=(10A)(10Omega)=100V`
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