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An inductor of inductance L and ressisto...

An inductor of inductance `L` and ressistor of resistance `R` are joined in series and connected by a source of frequency `omega`. Power dissipated in the circuit is

A

`((R^2+omega^2L^2))/V`

B

`(V^2R)/((R^2+omega^2L^2))`

C

`(V)/((R^2+omega^2L^2))`

D

`(sqrt(R^2+omega^2L^2))/(V^2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Power `(P) = VI cos phi =V(V/Z)(R/Z)`
`=(V^2R)/(Z^2)=(V^2R)/((R^2+omega^2L^2))`
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