Home
Class 12
PHYSICS
Consider the LR circuit shown in the fig...

Consider the LR circuit shown in the figure. If the switch S is closed at t = 0 then the amount of charge that passes through the battery between `t=0` and `t=L/R` is

A

`(2.7EL)/R^2`

B

`(7.3EL)/R^2`

C

`(EL)/(2.7R^2)`

D

`(EL)/(7.3R^2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`i=E/R (1-e^(-t//tau))` where `tau = L//R`
`(dq)/(dt)=E/R (1-e^(-t//tau))`
`int_0^(q)dq=intE/R (1-e^(-t//tau))dt`
`q=E/R[t-(e^(-t//tau))/(-1//tau)]_0^(tau)implies q=E/R[tau+tau/e-tau]`
`q=(E)/R(tau)/e=(LE)/(eR^2)=(LE)/(2.7R^2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

In the circuit as shown in the figure, switch S is added at t=0. Then:

In the circuit as shown in figure the switch is closed at t = 0 . At the instant of closing the switch

In given LR circuit the switch S is closed at time t=0 then

In the circuit shown in figure switch S is closed at time t=0 . The charge which passes through the battery in one time constant is

In the circuit as shown in figure the switch is closed at t = 0 . A long time after closing the switch

In the circuit shown in the figure, switch S is closed at time t=0 . Select the correct statements.

In the LR circuit as shown in figure, te switch is closed at t=0, mark the incorrect statement of the following

Consider the situation shown in figure.The switch is closed at t=0 when the capacitor C_(1) as a function of time t .