Home
Class 12
PHYSICS
The circuit is switched on at t=0, Find ...

The circuit is switched on at `t=0`, Find the time when energy stored in inductor becomes `1/n` tiimes of maximum energy stored in it:

A

`L/Rln((sqrtn)/(sqrtn-1))`

B

`L/Rln((sqrtn+1)/(sqrtn-1))`

C

`L/Rln((sqrtn)/(sqrtn+1))`

D

`L/Rln((sqrtn-1)/(sqrtn))`

Text Solution

Verified by Experts

The correct Answer is:
A

`U_(max)=1/2LI^2max`
`i=I_(max)(1-e^(-Rt//L))`
For U to be `(U_(max))/n` , i has to be `I_("max")/sqrtn`
`I_(max)/sqrtn=I_(max)(1-e^(Rt//L))`
`e^(-Rt//L)=1-1/sqrtn=(sqrtn-1)/sqrtn`
`-(Rt)/L=ln(sqrtn-1)/sqrtn`
`t=L/R ln ((sqrtn)/(sqrtn-1))`
Promotional Banner

Similar Questions

Explore conceptually related problems

Energy Stored In An Inductor

The capacitor shown in the figure is initially unchanged, the battery is ideal. The switch S is closed at time t= 0, then the time after which the energy stored in the capacitor becomes one - fourth of the energy stored in it in steady - state is :

A charged capacitor is connected to an inductor . At a particular instant, energy stored in inductor is 8/9 times of initial energy stored In capacitor . What is the ratio of initial charge on capacitor to that with instantaneous charge on capacitor ?

A simple LR circuit is connected to a battery at time t = 0 . The energy stored in the inductor reaches half its maximum value at time

Figure-5.150 shows LC circuit with initial charge on capacitor 200 mu C . If at t=0 switch is closed, find the first instant when energy stored in inductor becomes one third that of capacitor.

At t=0 switch S is closed . (a) After how much time , charge on capacitor is 50% of maximum charge stored on capacitor. (b) After how much time, energy stored in capacitor is halt of maximum energy stored in capacitor.

A circuit contains 50 muF capacitor and 20 mH inductor connected together with the help of a key which is open initially. Charge stored in the capacitor is 50 mC. Key is closed at t=0 . Calculate the minimum time interval in which energy stored in the inductor becomes equal to the energy stored in capacitor . Neglect any resistance in the circuit .