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An AC current is given by I = I(1) sin o...

An AC current is given by `I = I_(1) sin omega t + I_(2) cos omega t ` A hot wire ammeter will give a reading `:`

A

`(I_1+I_2)/(2sqrt2)`

B

`sqrt((I_1^2+I_2^2)/(2))`

C

`sqrt((I_1^2-I_2^2)/(2))`

D

`(I_1+I_2)/(sqrt2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Ammeter will read rms value
`i=sqrt(I_1^2+I_2^2)(I_1/sqrt(I_1^2+I_2^2)sinomegat+I_2/(sqrt(I_1^2+I_2^2))cosomegat)`
`i=sqrt(I_1^2+I_2^2)(cos phisin omegat+sinphicosomegat)`
`i=sqrt(I_1^2+I_2^2)sin(omegat+phi)" " (tan phi =I_2/I_1)`
`I_(rms)=I_0/sqrt2=sqrt((I_1^2+I_2^2)/(2))`
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