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A cathode emits 1.8xx10^(17) electron pe...

A cathode emits `1.8xx10^(17)` electron per second and all the electrons reach the anode when it Is given a positive potential of `400V`. Given `e=1.6xx10^(-19)`C, the maximum anode current is .

A

`2.7muA`

B

`29muA`

C

`72muA`

D

`29 mA`

Text Solution

Verified by Experts

The correct Answer is:
B
Current (i) `=Q/t =("ne")/(t) =1.8 xx10^(14) xx1.6 xx10^(-19)`
`= 28.8 xx10^(-6) A = 29muA`
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