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Photons of wavelength lambda are inciden...

Photons of wavelength `lambda` are incident on a metal. The most energetic electrons ejected from the metal are bent into a circular arc of radius R by a perpendicular magnetic field having a magnitude B. The work function of the metal is (Where symbols have their usual meanings) -

A

`(hc)/lamda-m_e+(e^2B^2R^2)/(2m_e)`

B

`(hc)/lamda+2m_e((eBR)/(2m_e))^2`

C

`(hc)/lamda-m_ec^2-(e^2B^2R^2)/(2m_e)`

D

`(hc)/lamda-2m_e((eBR)/(2m_e))^2`

Text Solution

Verified by Experts

The correct Answer is:
D
`N=(hc)/lamda=W+1/2m((ReB)/m)^2`
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