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What will be the ratio of de - Broglie w...

What will be the ratio of de - Broglie wavelengths of proton and `alpha` - particle of same energy ?

A

`2:1`

B

`1:2`

C

`4:1`

D

`1:4`

Text Solution

Verified by Experts

The correct Answer is:
A
`lamda=h/(sqrt(2mk))implieslamdaprop1/sqrtmimplieslamda_p/lamda_(alpha)=sqrt((m_(alpha))/m_p)=sqrt(4/1)=2/1`
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