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The de - Broglie wavelength of a particl...

The de - Broglie wavelength of a particle moving with a velocity `2.25 xx 10^(8) m//s` is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is (velocity of light is `3 xx 10^(8) m//s`

A

`1//8`

B

`3//8`

C

`5//8`

D

` 7//8`

Text Solution

Verified by Experts

The correct Answer is:
B
`lamda=h/(mv) and K_("particle")=1/2mv^2`
`implies K_("particle") = (vh)/(2lamda)`
`K_("photon") = (hc)/lamda`
`(K_("particle"))/(K_("photon"))=v/(2c)=(2.25 xx10^8)/(2xx3 xx10^8) =3/8`
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