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According to de broglie , the de broglie...

According to de broglie , the de broglie wavelength for electron in an orbit of radius `5.3xx10^(-11)` m of hydrogen atom is 1 Å. What is the principal quantum number for this electron ?

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
C
`2pirlamda=nlamdaimplies n =(2xx3.14 xx5.3 xx10^(-11))/(10^(-10))impliesn=3`
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