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A particle is droped from a height H. Th...

A particle is droped from a height H. The de-broglie wavelength of the particle as a function of height is proportional to

A

H

B

`H^(1//2)`

C

`H^(0)`

D

`H^(-1//2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Velocity of a body falling from a height H is given by
`v= sqrt(2gH)`
We know that de-Broglie wavelength
`lamda=h/(mv)=h/(msqrt(2gH))implies h/(msqrt(2g)sqrtH)`
Here, `h/(msqrt2g)` is a constant say . K.
So, `lamda=K1/(sqrtH)implies lamdaprop 1/(sqrtH)implies lamda prop H^(-1//2)`
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