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The log - log graph between the energy E...

The log - log graph between the energy `E` of an electron and its de - Broglie wavelength `lambda` will be

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
C
`lamda = 1/(sqrt(2mE))implies log lamda=log""h/(sqrt(2m))+log""1/sqrtE`
`implies loglamda=-1/2logE+log""h/(sqrt(2m))`
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