The de - Broglie wavelength of a neutron...

The de - Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature `T ("kelvin")` and mass `m`, is

A

`h/(sqrt(mkT))`

B

`h/(3sqrt(mkT))`

C

`(2h)/(3sqrt(mkT))`

D

`(2h)/(sqrt(mkT))`

Verified by Experts

The correct Answer is:

B

Kinetic energy of neutron with thermal equilibrium is, `KE=3/2kT=P^2/(2m)impliesP=sqrt(2mkT)`
`lamda=h/P=h/(sqrt(3mkT))`

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