A photon of wavelength 6630 Å is inciden...

A photon of wavelength `6630 Å` is incident on a totally reflecting surface . The momentum delivered by the photon is equal to

A

`6.63 xx10^(-27)` kg-m/s

B

`2xx10^(-27)` kg-m/s

C

`10^(-27)` kg-m/s

D

None of these

Verified by Experts

The correct Answer is:

B

`P=h/lamda`
Change in momentum
`DeltaP = P - (-P) = (2P )/lamda=(2xx6.6xx10^(-34))/(6630 xx10^(-10))`
`= 2 xx10^(-27) kg - mg//sec`

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